4n^2+10n-87=0

Solution for 4n^2+10n-87=0 equation:

4n^2+10n-87=0

a = 4; b = 10; c = -87;
Δ = b2-4ac
Δ = 102-4·4·(-87)
Δ = 1492
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1492}=\sqrt{4*373}=\sqrt{4}*\sqrt{373}=2\sqrt{373}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{373}}{2*4}=\frac{-10-2\sqrt{373}}{8}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{373}}{2*4}=\frac{-10+2\sqrt{373}}{8}
$